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4x^2+12.5x-5.25=0
a = 4; b = 12.5; c = -5.25;
Δ = b2-4ac
Δ = 12.52-4·4·(-5.25)
Δ = 240.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.5)-\sqrt{240.25}}{2*4}=\frac{-12.5-\sqrt{240.25}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.5)+\sqrt{240.25}}{2*4}=\frac{-12.5+\sqrt{240.25}}{8} $
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